def bruteForceMultioly(A, B) :
    C = []
    n = len(A)
    for i in range(0, n) :
        row = []        
        for j in range(0, n) :
            result = 0
            for k in range(0, n) :
                result += A[i][k] * B[k][j]
            row.append(result)
        C.append(row)
    return C